SOLUTION: Which equation has a graph that is perpendicular to the graph of 7x = 14y-8?
1- y=-2x-7
2- y= -1/2x+4
3-y= 1/2x+1
4-y=2x+9
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Question 930443: Which equation has a graph that is perpendicular to the graph of 7x = 14y-8?
1- y=-2x-7
2- y= -1/2x+4
3-y= 1/2x+1
4-y=2x+9
Answer by algebrahouse.com(1659) (Show Source): You can put this solution on YOUR website!
Perpendicular lines have slopes which are negative reciprocals.
Slope-intercept form is y = mx + b
m is the slope
b is the y-intercept
7x = 14y - 8
7x + 8 = 14y {added 8 to each side}
(1/2)x + (8/14) = y
slope is 1/2
A line perpendicular would have a slope of -2 {the negative reciprocal of 1/2}
#1 y = -2x - 7 {it is the only one with a slope of -2}
For more help from me, visit: www.algebrahouse.com
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