SOLUTION: Express x^2-5x+6 in the form of (x-a)^2-b. Hence state the coordinates of the turning point of the curve y=x^2-5x+6. I really don't understand how to work out the turning poin

Question 919341: Express x^2-5x+6 in the form of (x-a)^2-b. Hence state the coordinates of the turning point of the curve y=x^2-5x+6.

I really don't understand how to work out the turning point so guidance would be very helpful. Thanks.
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
the vertex form of a Parabola opening up(a>0) or down(a<0),
. V(h, k)
Completing the Square to Obtain the Vertex Form:
y = ax^2 + bx + c = 0
y = x^2-5x+6 = 0 5/2 the x-value for the Vertex
y = (x - 5/2)^2 - (5/2)^2 + 6 = 0
y = (x - 5/2)^2 - 25/4 + 24/4= 0 = -25/4
y = (x - 5/2)^2 - 1/4 = 0
V(5/2, -1/4)

RELATED QUESTIONS
i) Express {{{6 + 4x - x^2}}} in the form {{{a - (x + b)^2}}}, where a and b are... (answered by ewatrrr)

A curve has equation y = (x^2-5x+7)/(x-3). Find the range of y for real x. Hence, or... (answered by Boreal)

Find the coordinates of the turning point of the curve {{{y = 6 + 4x - x^2}}} (by... (answered by nerdybill,ewatrrr)

The question is: The quadratic function f is defined by f(x) = {{{4x^2 +5x +2}}} a) (answered by Alan3354)

a)Express x^2 -10x + 32 in the form (x+a)^2 + b ,giving the values of a and b. b)Sketch... (answered by Theo)

Question 4 Given y = x^2-x-6 a) Determine the x-intercepts. (answered by rothauserc)

express the following functions in turning point form and hence sketch their graphs. y (answered by checkley77)

This is my question:express each of the following in the form y = a(x - h)^2 + k. Hence... (answered by kietra)

6) Given the curve y = x^3 - 3x^2 - 9x+11, find dy/dx.Hence obtain a) the x-coordinates... (answered by Alan3354,math_helper)