SOLUTION: How do I figure out the graph for: f(x) = 3(2^x)-6
I know that x=-6 is the horizontal asymptote
when I go to make a t-table my points are all over the place and not consisten
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Question 917221: How do I figure out the graph for: f(x) = 3(2^x)-6
I know that x=-6 is the horizontal asymptote
when I go to make a t-table my points are all over the place and not consistent.
like plugging in x=1 results in 0. x=2 results in 6...
What is the proper way to figure out this graph?
Thank you
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
The factor 3, just stretches the graph vertically. The minus 6 moves the graph downward by 6 units.
Work with easy values to help get good points to sketch the graph.
x____________f(x)
-2_________
-1_________
0__________
1__________
2__________
For comparison this is 2^x:
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