SOLUTION: Find the points on the graph of the function that are closest to the given point.
f(x) = (x + 2)^2, (7, 8)
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Question 916549: Find the points on the graph of the function that are closest to the given point.
f(x) = (x + 2)^2, (7, 8)
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find the points on the graph of the function that are closest to the given point.
f(x) = (x + 2)^2, (7, 8)
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Points on the graph have the form (x,(x+2)^2)
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distance = sqrt[(7-x)^2+(8-(x+2)^2)^2
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d = sqrt[(49-14x+x^2 + (64-16(x+2)^2+(x+2)^4)]
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Simplify the radicand.
Take the derivative.
Set it to zero and solve for "x" and then the corresponding f(x).
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Cheers,
Stan H.
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