SOLUTION: Solve the system by graphing. 4x + 2y = 10 y = 4

Algebra.Com
Question 90781: Solve the system by graphing.
4x + 2y = 10
y = 4

Answer by praseenakos@yahoo.com(507)   (Show Source): You can put this solution on YOUR website!
Question:

Solve the system by graphing.
4x + 2y = 10
y = 4


Answer:
If you are doing it in a graph paper, what you have to do is,
Rewrite the given equations in terms of x as follows.
4x + 2y = 10
==> y = 5 - 2x
y = 4
Now put some arbitrary values for x in the (1) and (2) and find out the corresponding y values.

For(1), when x = 0, y = 5 - 2*0 = 5

when x = 1, y = 5 - 2*1 = 5 - 2 = 3

When x = 2, y = 5 - 2*2 = 5 - 4 = 1

Now plot this values on the graph paper.

Similarly find out x and y values for the second equation and plot the graph.


Then the graphs will come like this....







Here you can see that the lines intersect at a single point.
Coordinates of that point of intersection is (0.5,4) which is the solution of the given equations.

To check your solution, substitute the values, x = 0.5 and y = 4 in the given equations....then you can see that these values will satisfy the given equation.


Hope you found the explanation useful.


Regards.

Praseena.

RELATED QUESTIONS

Solve the system by graphing. 4x+2y=10... (answered by bucky)
Solve the system by graphing. 4x + 2y = 10 y = 4 (answered by Edwin McCravy)
Solve the system by graphing both lines on one coordinate system. 4x+y=4... (answered by Alan3354)
Can you please help me solve the equation...instructions...solve the system by graphing. (answered by checkley75)
Solve the system by graphing. 4x+2y=10 y=4 I need to solve the equations and... (answered by checkley71)
Solve the system by graphing.4x + 2y = 10 Solve the system by substitution. 3x – (answered by checkley71)
solve the system by graphing y=-2x+3 4x+2y=-4 Use the graphing tool graph the... (answered by solver91311,MathLover1)
Solve the system by graphing 2x – y = 4 4x – 2y =-8 (answered by checkley75)
help solve the system of equations by graphing y+2x=-4... (answered by Jk22)