SOLUTION: I'm trying to graph y=(x-2)^3+1 but when I plug in the numbers 0 thru 4, it's not looking long any kind of function

Question 901510: I'm trying to graph y=(x-2)^3+1 but when I plug in the numbers 0 thru 4, it's not looking long any kind of function
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
That is a simple cubic equation, and what would have been the origin (0,0) for y=x^3, has now been moved to (2,1) instead; along with the entire graph being moved the same way. You should find very little if any trouble finding the y values corresponding to integer assignments for x from 0 to 4. Note, you are exponentiating to a whole number so this is uncomplicated.

Model Cubic Function,

Specific graph of

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