SOLUTION: Graph each of the following equations, using the intercept method. See Example 7 (p 534) in the text for reference. 28) 2x + 3y = 6

Question 87451: Graph each of the following equations, using the intercept method. See Example 7 (p 534) in the text for reference.
28) 2x + 3y = 6

Found 2 solutions by checkley75, rapaljer:
Answer by checkley75(3666) (Show Source): You can put this solution on YOUR website!
2X+3Y=6
3Y=-2X+6
Y=-2X/3+6/3
Y=-2X/3+2
SETTING X=0 WE GET
Y=-2*0/3+2
Y=2 THUS WE HAVE THE POINT (0,2)
NOW SET Y=0 & SOLVE FOR X
0=-2X/3+2
-2X/3=-2
-2X=-6
X=-6/-2
X=3 THUS WE HAVE THE POINT (3,0).
NOW PLOT THESE 2 POINTS AND DRAW A LINE THROUGH THEM THUS:
(graph 300x200 pixels, x from -6 to 5, y from -10 to 10, y = -2x/3 +2).
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
2x + 3y = 6

Let x=0, and find y. 3y=6, so y=2

Let y=0, and find x. 2x=6, so x=3

Graph these two points. It should look like this:

R^2 Retired from SCC
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