SOLUTION: Identify the vertex, axis of symmetry, and intercepts for the graph of the function. x=y^2+6y-1 (use completing the square method) (then graph).

Question 867911: Identify the vertex, axis of symmetry, and intercepts for the graph of the function. x=y^2+6y-1 (use completing the square method) (then graph).
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Identify the vertex, axis of symmetry, and intercepts for the graph of the function. x=y^2+6y-1 (use completing the square method) (then graph).
***
x=y^2+6y-1
x=(y^2+6y+9)-9-1
x=(y+3)^2-10
(y+3)^2=x+10
This is an equation of a parabola that opens right
vertex:(-10,-3)
axis of symmetry:y=3
..
x-intercepts:
set y=0
x=y^2+6y-1
x=-1
..
y-intercepts
set x=0
(y+3)^2=x+10
y+3=�√10
y=-3�√10
y≈-6.16
or
y≈0.16
..
see graph below:
y=�(x+10)^.5-3

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