SOLUTION: Hello I need to know how to complete: Graph the equation y=x(squared) + 2 thanks

Question 86475: Hello I need to know how to complete:
Graph the equation y=x(squared) + 2
thanks

Answer by chitra(359) (Show Source): You can put this solution on YOUR website!
The given equation is y = x(squared) + 2

==> y =

The given equation is a quadratic in "x". The graph of any quadratic equation will always be a parabola.

Hence, the graph look like this:

Hence, the solution..

This can also be worked in another way...

Let f(x) =

Given the equation just plug in the values for x and then make the table for x and f(x). Then plot all these points on the number line along the co-ordinate axes...

For example when x = 0, f(x) = 2

x = 1 , f(x) = 3

x = 2 . f(x) = 5

x = 3 , f(x) = 10

And similarly for the negative values..

x = -1 , f(x) = 3

x = -2 , f(x) = 5

x = -3 , f(x) = 10

f(x) will have the same values, since the given function is an even function..

Thus, the solution...

Regards

RELATED QUESTIONS
hello.. umm i need help, i need to solve an equation that i have to graph. i get the... (answered by lynnlo)

Hello, need an explanation on how to find the x intercepts, and the vertex of this... (answered by stanbon)

I know that the following equation will result in a circle graph (the teacher's key says... (answered by nerdybill)

y=.5xsquared - 6x + 12 I need to get it into the equation of (x-x1) quantity squared + (answered by josmiceli)

Hello, I am trying to figure out how to graph this following equation. y=(x-2)^2(x+5)... (answered by josgarithmetic)

Graph the quadratic equation by plotting points? Graph the quadratic equation by... (answered by jim_thompson5910,ewatrrr)

I need to know how to solve & graph this linear equation: x-y=-3 Pleas help!!... (answered by mangopeeler07)

Hello I need help on graphing this equation. It says to graph without a calculator but I (answered by jim_thompson5910,edjones)

Please help I don't know how to graph this Graph the following equation: Y = |x| -... (answered by Alan3354,ikleyn)