SOLUTION: Sketch the parabola {{{y=x^2+x-6}}} by using its intercepts Please show all steps

SOLUTION: Sketch the parabola {{{y=x^2+x-6}}} by using its intercepts Please show all steps

Algebra.Com

Question 851070: Sketch the parabola by using its intercepts
Please show all steps
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
The leading term tells you the graph opens upward and so vertex is a minimum, and you should find the quadratic factorable.

zeros are x=2 and x=-3.
y is negative between x= 2 and x=-3, but positive outside that interval.
The axis of symmetry is

RELATED QUESTIONS
Sketch the parabola {{{y=x^2+x-6}}} by using its intercepts Please show all... (answered by josgarithmetic)

Sketch the parabola {{{y=x^2+x-6}}} by using its intercepts Please show all... (answered by josgarithmetic)

Sketch the parabola {{{ y=x^2+x-6 }}} by using its intercepts. Please show all steps... (answered by ankor@dixie-net.com)

Graph the linear function by finding x-and y-intercepts. 4x=6y+2 please (answered by stanbon,Boreal)

I need your help. Can someone please graph this for me? Find the vertex and intercepts (answered by Alwayscheerful)

Find the vertex and intercepts for each parabola, and sketch its graph. y= -x^2 -3x -... (answered by stanbon)

Determine the y-intercept and x-intercepts of the parabola represented by the following... (answered by Boreal)

Parabola questions are the hardest can someone help me figure this out show steps please. (answered by ewatrrr)

Given y=3x^2+6x Please explain the process in steps. Thanks! A.) find the... (answered by MathLover1)