SOLUTION: Write equation for the line . Use slope intercept form if it its possible. # 1 through (-1,4) perpendicular to 9x+5y=11 this is what i have done so far am i correct 9x+5y

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Question 84055: Write equation for the line . Use slope intercept form if it its possible.
# 1
through (-1,4) perpendicular to 9x+5y=11
this is what i have done so far am i correct
9x+5y=11
5y=-9x+11
y=-(9)/(5)+(11)/(5)
so then i use the recipriocal slope which will be (5)/(9) and use the point that they gave me. so now i do the following:
y = mx+b
4 = (5)/(9) * (-1) +b
(41)/(9)=b
y= (5)/(9)x+(41)/(9)

#2
through (3,-5),parallel to y =4
for this one ihave no idea?

Found 2 solutions by jim_thompson5910, Edwin McCravy:
Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
#1 correct

#2
The equation of really looks like where the slope is 0
Solved by pluggable solver: Finding the Equation of a Line Parallel or Perpendicular to a Given Line


Since any two parallel lines have the same slope we know the slope of the unknown line is (its from the slope of which is also ). Also since the unknown line goes through (3,-5), we can find the equation by plugging in this info into the point-slope formula

Point-Slope Formula:

where m is the slope and (,) is the given point



Plug in , , and



Distribute



Multiply



Subtract from both sides to isolate y

Combine like terms

So the equation of the line that is parallel to and goes through (,) is


So here are the graphs of the equations and



graph of the given equation (red) and graph of the line (green) that is parallel to the given graph and goes through (,)




So the line that is parallel to and goes through (3,-5) is
It's hard to see, but there are 2 horizontal lines at y=4 and y=-5
Answer by Edwin McCravy(20060)   (Show Source): You can put this solution on YOUR website!
Write equation for the line . Use slope intercept form if it its possible.
# 1
through (-1,4) perpendicular to 9x+5y=11
this is what i have done so far am i correct
9x+5y=11
5y=-9x+11
y=-(9)/(5)+(11)/(5)
so then i use the reciprocal slope with the opposite sign
which will be (5)/(9) and use the point that they gave me. so now i do the following:
y = mx+b
4 = (5)/(9) * (-1) +b
(41)/(9)=b
y= (5)/(9)x+(41)/(9) 

That one is correct!

#2
through (3,-5),parallel to y =4
for this one i have no idea?

y = 4 is this horizontal line

 

now plot the point (3,-5)

 
 
Now draw a green line parallel to
the given line through that point.
It will also be horizontal:



The equation of any horizontal line is y = b,
where b is the y-coordinate of any and every 
point on the line.  So since (3,-5) is on the 
line and it has y-coordinate -5, the equation
of the green line is y = -5.

Edwin
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