SOLUTION: Graphing Y=x^2+3x+2 Identify the vertext and the axis of symmetry

Algebra.Com
Question 83726: Graphing Y=x^2+3x+2
Identify the vertext and the axis of symmetry

Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
Solved by pluggable solver: Completing the Square to Get a Quadratic into Vertex Form


Start with the given equation



Subtract from both sides



Factor out the leading coefficient



Take half of the x coefficient to get (ie ).


Now square to get (ie )





Now add and subtract this value inside the parenthesis. Doing both the addition and subtraction of does not change the equation




Now factor to get



Distribute



Multiply



Now add to both sides to isolate y



Combine like terms




Now the quadratic is in vertex form where , , and . Remember (h,k) is the vertex and "a" is the stretch/compression factor.




Check:


Notice if we graph the original equation we get:


Graph of . Notice how the vertex is (,).



Notice if we graph the final equation we get:


Graph of . Notice how the vertex is also (,).



So if these two equations were graphed on the same coordinate plane, one would overlap another perfectly. So this visually verifies our answer.




RELATED QUESTIONS

Write the following quadratic function in the vertext form. Then, identify the axis of... (answered by josgarithmetic)
Identify the vertex and axis of symmetry:... (answered by josgarithmetic)
Identify the vertex, axis of symmetry and min/max value... (answered by lwsshak3)
Identify the y-intercept and the axis of symmetry for the graph of... (answered by rfer)
Identify the vertext for graph of... (answered by scott8148,lwsshak3)
Identify the vertex, axis of symmetry, and direction of opening for... (answered by stanbon)
how to graph and identify the focus, directrix, and axis of symmetry of x=-y^2 (answered by lwsshak3)
F(x)=10x^2+40x+42 identify the y intercept and the axis of... (answered by Fombitz)
Identify the axis of symmetry, create a suitable table of values, then sketch the graph... (answered by checkley75)