SOLUTION: for the quadratic function: f(x)=3(x+4)^2 state the vertex:( , ) does the parabola open up or down. the function has ___ real zeros

Algebra ->  Algebra  -> Graphs -> SOLUTION: for the quadratic function: f(x)=3(x+4)^2 state the vertex:( , ) does the parabola open up or down. the function has ___ real zeros      Log On

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Question 83339: for the quadratic function:
f(x)=3(x+4)^2
state the vertex:( , )
does the parabola open up or down.
the function has ___ real zeros
Answer by jim_thompson5910(21667) About Me  (Show Source):
You can put this solution on YOUR website!
Using the vertex form

y=a%28x-h%29%5E2%2Bk where a states the shape and direction, and (h,k) is the vertex,

The equation f%28x%29=3%28x%2B4%29%5E2 which also looks like f%28x%29=3%28x-%28-4%29%29%5E2%2B0, has a vertex at (-4,0). Also, since a>0, the graph opens up. So here's the graph to visually sum it up

drawing%28400%2C400%2C-7%2C3%2C-5%2C5%2C%0D%0A+graph%28+400%2C+400%2C+-7%2C+3%2C+-5%2C+5%2C3%28x%2B4%29%5E2%29%2C%0D%0Ablue%28circle%28-4%2C0%2C0.08%29%29%29%2C%0D%0Ablue%28circle%28-4%2C0%2C0.1%29%29%0D%0Ablue%28circle%28-4%2C0%2C0.08%29%29%29%2C%0D%0Ablue%28circle%28-4%2C0%2C0.05%29%29%29%29+ graph of y=3%28x%2B4%29%5E2 with the vertex (blue dot)