SOLUTION: I am stumped on this problem, its kind of long so bear with me. The problem is about the relationship between "spawners" and "recruits" R=APe^-BP R is the number of recruits, P

Question 830849: I am stumped on this problem, its kind of long so bear with me.
The problem is about the relationship between "spawners" and "recruits"
R=APe^-BP
R is the number of recruits, P is the number of spawners.
It is given that A=4 and B=0.7
Q:Make a graph of R against P (Assume there are at most 3000 spawners)
Now I get to R=4Pe^-0.7P. I'm trying to use an online graphing calculator because i do not have a regular one. I don't know what to use as values for x and y (or P and R) and also i have no idea what the 3000 means or where im supposed to use it.
Again sorry this is long and complicated but i cannot get through it please help or give some sort of direction please.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
I am stumped on this problem, its kind of long so bear with me.
The problem is about the relationship between "spawners" and "recruits"
R=APe^-BP
R is the number of recruits, P is the number of spawners.
It is given that A=4 and B=0.7
Q:Make a graph of R against P (Assume there are at most 3000 spawners)
Now I get to R=4Pe^-0.7P. I'm trying to use an online graphing calculator because i do not have a regular one. I don't know what to use as values for x and y (or P and R) and also i have no idea what the 3000 means or where im supposed to use it.
------
Graph y = 4x*e^(-0.7x) as 4x*(2.718)^(-0.7x)
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Cheers,
Stan H.

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