SOLUTION: Okay, I really need someone's help with this. I have asked everyone I know if they could help. And they CAN'T. Solve the linear inequalities by graphing: 3x+4y<=12 x+3y<=6

Question 82635: Okay, I really need someone's help with this. I have asked everyone I know if they could help. And they CAN'T.
Solve the linear inequalities by graphing:
3x+4y<=12
x+3y<=6
x=>0
y=>0
PLEASE HELP!!!!
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!

Look at the 3rd and 4th first. simply says that x is
never negative. says y is never negative. The area
on the graph where both are true is the upper right quadrant, so
all solutions must be there as a restriction.
Solve the 1st and 2nd for y.

-------------

now plot these

The solution is the area below the lines between (0,2) and (4,0)
Note that both these points are solutions and neither one
violates or .
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