You can
put this solution on YOUR website!The equation of a line can be written in slope-intercept form, y=mx+b, where "m" is the slope and "b" is the y-intercept of (0,4). Since you are given the y-intercept, all you need is the slope, which is

.
In this case,

.
The equation of the line is therefore:

.
R^2 at SCC
You can
put this solution on YOUR website!Would someone please explain step by step for me please, so I can see how to set up problem. Thanks
Write the equation of the line with x-intercept (12,0)and y-intercept (0,4).
1. (12, 0) and (0,4)
We first plot those two points and draw a line
through them to find out if it is vertical or
not. The equations of all lines can be placed
in slope-intercept form except the equations
for vertical lines. This is the graph we get:
We see that it is not vertical. So we can proceed
as usual:
We are to find an equation of the line containing
the points (12,0) and (0,4)
Use the slope formula:
y2 - y1
m = —————————
x2 - x1
where (x1, y1) = (12,0) and (x2, y2) = (0,4)
(4) - (0) 4 -1
m = ——————————— = ————— = ———— =
(0) - (12) -12 3
Now substitute in the point slope formula:
y - y1 = m(x - x1)
y - 0 =
(x - (12) )
y =
(x - 12)
y =
x + 4
That's the equation in the slope-intercept
form because we can compare it with
y = mx + b
and see that its slope m is
and its
y-intercept (0,b) is the point (0,4)
Edwin