I'm learning how to write my "results" in slope-intercept form. And I'm having a little difficulty trying to get these worked out and was wondering if I could get some assistance. (0,5), m =Substitute in the point slope formula: y - y1 = m(x - x1) where x1 = 0 and y1 = 5 y - 5 = (x - (0) ) y - 5 = x y = x + 5 That's the equation in the slope-intercept form because we can compare it with y = mx + b and see that its slope m is and its y-intercept (0,b) is the point (0,5) --------------------------------------- 1. (-1, 3) and (4,-2) We first plot those two points and draw a line through them to find out if it is vertical or not. The equations of all lines can be placed in slope-intercept form except the equations for vertical lines. This is the graph we get: We see that it is not vertical. So we can proceed as usual: We are to find an equation of the line containing the points (-1,3) and (4,-2) Use the slope formula: y2 - y1 m = ————————— x2 - x1 where (x1, y1) = (-1,3) and (x2, y2) = (4, -2) (-2) - (3) -5 -5 m = —————————— = ————— = ———— = -1 (4) - (-1) 4+1 5 Now substitute in the point slope formula: y - y1 = m(x - x1) y - 3 = (-1)(x - (-1) ) y - 3 = -(x + 1) y - 3 = -x - 1 y = -x + 2 That's the equation in the slope-intercept form because we can compare it with y = mx + b and see that its slope m is -1 and its y-intercept (0,b) is the point (0,2) --------------------------------------- (2,-3) and (2,4) We plot those two points and draw a line through them: It is vertical, so we can't go the usual route. Since vertical lines are the only kind of lines which don't have slopes, there is no slope-intercept form. But we can still write the equation. It is simply this: x = 2 because every point on that line has x-coordinate 2. So x = 2 tells the story of every point on the line, so that's all there is to the equation of that vertical line. Edwin