SOLUTION: Hello, I was wondering if you could explain how to Write the equation of a line parallel to the given line but passing through the given point. y=-2x-4; (1,3)? so far I have Y=-2x

Question 813747: Hello, I was wondering if you could explain how to Write the equation of a line parallel to the given line but passing through the given point.
y=-2x-4; (1,3)? so far I have Y=-2x-4; (1, 3)
m= 1, (1, 3)
y-y1=m(x-x1)
y-3=1(x-1)
y-3=x-1
y=x+4
I am not sure if I have done this right or not.
Thank you
Found 2 solutions by richwmiller, josgarithmetic:
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
m=-2
y=mx+b
the slope will be the same
The slope of y=-2x-4 is -2
plug it in.
y=-2x+b
now plug in x and y 1 and 3
3=-2+b
solve for b
5=b
now plug in 5 for b
y=-2x+5

Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
Line y=-2x-4, want line parallel to it, passing through (1,3).

Given line is in slope-intercept form, indicating slope is -2. The slope of the line we want is also .

You have chose to continue the solution using Point-Slope form for a line, so I will do so also.

You already know that m is for slope. Your point (,) is the point (1,3). You must KNOW now that m=-2. Substitute and simplify:

---------Your Answer.

PARALLEL, PARALLEL, PARALLEL, PARALLEL,... Same Slope!
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