SOLUTION: How do you solve by completing the square 3x^2+20x-3=0

Question 800660: How do you
solve by completing the square
3x^2+20x-3=0
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
3x^2+20x-3=0
3x^2+20x=3
/3
x^2+(20/3)x=1
Third term = (1/2 *20/3)^2
=(10/3)^2
=100/9
x^2+(20/3)x +100/9 =1+100/9
(x+(10/3))^2= 109/9
take the square root
x+ (10/3) = +/- sqrt(109/9)
x= -(10/3) +/- sqrt(109)/3

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