solve the following system of equations by graphing 3x - 2y = 8 2x - 3y = 7 Make a table of points for each equationm: In the first, I arbitrarily chooss -2 for x and substitute: 3x - 2y = 8 3(-2) - 2y = 8 -6 - 2y = 8 -2y = 14 y = -7 So one point on the graph of the first equation in (-2,-7) I arbitrarily chooss 2 for y and substitute: 3x - 2y = 8 3x - 2(2) = 8 3x - 4 = 8 3x = 12 x = 4 So another point on the graph of the first equation in (4,2) I arbitrarily chooss 0 for x and substitute: 3x - 2y = 8 3(0) - 2y = 8 0 - 2y = 8 -2x = 8 x = -4 So a third point on the graph of the first equation in (0,-4). So plot those points, (-2,-7), (4,2), (0,-4) and draw a line through them:In the second equation, I arbitrarily chooss -1 for x and substitute: 2x - 3y = 7 2(-1) - 3y = 7 -2 - 3y = 7 -3y = 9 y = -3 So one point on the graph of the second equation in (-1,-3) I arbitrarily chooss 1 for y and substitute: 2x - 3y = 7 2x - 3(1) = 7 2x - 3 = 7 2x = 10 x = 5 So another point on the graph of the second equation in (5,1) I arbitrarily chooss -4 for x and substitute: 2x - 3y = 7 2(-4) - 3y = 7 -8 - 3y = 7 -3x = 15 x = -5 So a third point on the graph of the second equation in (-4,-5). So plot those points, (-1,-3), (5,1), (-4,-5) on the same set of axes and draw a line through them: Through the point where those two lines cross, draw a vertical line: Notice that the vertical line crosses the x-axis at the value 2. So the x value of the solution is 2. Also through the point where those two lines cross, draw a horizontal line: Notice that the horizontal line crosses the y-axis at the value -1. So the y value of the solution is -1. The solution is therefore (x, y) = (2, -1) Now let's check to see if this is the correct solution by substituting in BOTH equations: Substituting in the first: 3x - 2y = 8 3(2) - 2(-1) = 8 6 + 2 = 8 8 = 8 That checks: Substituting in the second: 2x - 3y = 7 2(2) - 3(-1) = 7 4 + 3 = 7 7 = 7 That checks, too. So we know that this is the correct solution. Edwin