# SOLUTION: Find the equation of a line passing through the points (3,6) and perpendicular to the line y=x+7

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 Click here to see ALL problems on Graphs Question 77766: Find the equation of a line passing through the points (3,6) and perpendicular to the line y=x+7Answer by checkley75(3666)   (Show Source): You can put this solution on YOUR website!Y=mX+b WHERE (M)=SLOPE & (b)=Y INTERCEPT. TO FIND A LINE PERPENDICULAR TO THE LINE Y=X+7 IS -1. NOW REPLACE X BY 3 & Y BY 6 AND SOLVE FOR THE Y INTERCEPT(b). THUS: 6=-3+b b=6+3 b=9 Y INTERCEPT. thus the equation for this line is y=-x+9 [the green line] Y=X+7 [the red line] (graph 300x300 pixels, x from -10 to 10, y from -10 to 10, y = x +7 and y = -x +9).