SOLUTION: Please explain how to graph this parabola: Y = (x-4)^2

SOLUTION: Please explain how to graph this parabola: Y = (x-4)^2 - 3

Question 775701: Please explain how to graph this parabola:
Y = (x-4)^2 - 3
Answer by swincher4391(1107) (Show Source): You can put this solution on YOUR website!
This is in a form we call vertex form.
Y = (x-h)^2 + k where (h,k) is the vertex.
Given that, we know that the vertex is (4, -3)

If we can find out the two y-intercepts [or zeroes] we can connect the dots into a parabola and graph.
Solve for x.
y + 3 = (x-4)^2
+-sqrt(y+3) = x -4
+- sqrt(y+3) + 4 = x
Put y =0,
4 +- sqrt(3) = 2.3 and 6.7

So we have (2.3,0), (4,-3) (6.7,0)
Connect and we've got it.
RELATED QUESTIONS
A parabola has intercepts of x = -2, x = 3, and y = -4. a. Write the intercept form of (answered by josgarithmetic,Edwin McCravy)

Graph the parabula {{{y=-x^2-4x+1}}} Please explain how to do this also... (answered by Alan3354)

Please explain to me how to graph the line: x=-4, and also how to graph the line: y=2 (answered by stanbon)

Please help me solve this parabola using the vertex, please explain how to find the... (answered by Alan3354)

How do u graph this Parabola:... (answered by nyc_function)

How to graph this equation (2/3) x = 4 + y (answered by Alan3354)

y+3=-1/2(x-2)^2 how to graph the... (answered by stanbon)

how to graph x=y^2-6y+8 This is parabola (answered by lwsshak3)

Could you please explain how to do this. graph this equation... (answered by edjones)