SOLUTION: what is the equation of the axis of symmetry of the graph y=x^2-4x+1?

SOLUTION: what is the equation of the axis of symmetry of the graph y=x^2-4x+1?

Algebra.Com

Question 77277: what is the equation of the axis of symmetry of the graph y=x^2-4x+1?
Answer by Nate(3500) (Show Source): You can put this solution on YOUR website!
y = x^2 - 4x + 1
This is a parabola that is vertical.
The line of symmetrical is vertical, so the equation must x = something ....
Vertex(-b/2a,f(x))
V(-(-4)/(2*1),f(x))
V(4/2,f(x))
V(2,f(2))
x = 2

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