SOLUTION: I need to find the vertex of f(x)=(x+3)^2
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Question 767865: I need to find the vertex of f(x)=(x+3)^2
Found 2 solutions by algebrahouse.com, josgarithmetic:
Answer by algebrahouse.com(1659) (Show Source): You can put this solution on YOUR website!
Vertex Form is y = a(x - h)² + k
the vertex has coordinates of (h,k)
In f(x) = (x + 3)²
since 3 is positive, that means the value of h is -3, to make it +3 and
k is of course 0
Vertex is (-3,0)
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Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Consider the standard reference parabola, . The center is at (0, 0). Adding or subtracting a number on x will shift right or left. This shift is the whole graph.
will shift the whole graph, including vertex, c units to the right. This means the vertex would be (c, 0).
YOUR task now is to conclude what is the vertex of .
(?, 0).
What point is it?
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