SOLUTION: How do i graph this equation?
y=4/3x2+8/3x-8/3
Please give me the Vertex and 4 additional points, 2 on each side of the vertex so i can graph it.
Thanks!
Algebra.Com
Question 762675: How do i graph this equation?
y=4/3x2+8/3x-8/3
Please give me the Vertex and 4 additional points, 2 on each side of the vertex so i can graph it.
Thanks!
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
The 
-coordinate of the vertex of \ =\ ax^2\ +\ bx\ +\ c)
is given by 
The 
-coordinate of the vertex of , namely 
, is given by the value of the function at 
, namely:
\ =\ a(x_v)^2\ +\ b(x_v)\ +\ c)
.
Now that you have the coordinates of the vertex, plot )
.
As it turns out, is an integer in this problem, so pick another value for that is 1 larger than . Evaluate the function at this value:
\ =\ a(x_v\,+\,1)^2\ +\ b(x_v\,+\,1)\ +\ c)
.
Then plot \right))
. Use the property of symmetry to determine that if is a point on your graph, \right))
must also be on the graph.
Calculate 
and repeat the above process for your other two points, giving you 5 points in all including the vertex.
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
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