SOLUTION: Solve A chemist needs 150 milliliters of a 43% solution but has only 13% and 58% solutions available. Find how many milliliters of each that should be mixed to get the desired

Question 760246: Solve
A chemist needs 150 milliliters of a 43% solution but has only 13% and
58% solutions available. Find how many milliliters of each that should be
mixed to get the desired solution.
Please show detailed steps. Thank you :)
Answer by ramkikk66(644) (Show Source): You can put this solution on YOUR website!
Let the final mix have x ml of 13% solution and y ml of 58% solution.
(it is given that the final mix is 150 ml)
x ml of the mix is equivalent to a 0.13x solution (13% solution of say alcohol means that 100 ml of the solution will have 13 ml of alcohol and the rest as the solvent i.e. water).
Similarly, y ml of the mix is equivalent of a 0.58x solution and contains 0.58y ml of solute.
But the final mix (150 ml) is 43% strong. i.e it contains 150*0.43 ml of the solute.
Therefore,

Solving for simultaneous equations for x and y from equations 1 and 2, we get that x = 50 and y = 100.
(If you don't know how to solve simultaneous equations, the steps are:
eq (1) rewritten as: or eq (3)
eq (2) rewritten as: eq (4)
Subtracting (3) from (4), or
Since x + y = 150 and y = 100,

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