SOLUTION: The graph of a quadratic function passes through B(4,6), and the zeros of the function are 5 and 6. Write an equation of the graph in general form. This question makes no sen

Question 759456: The graph of a quadratic function passes through B(4,6), and the zeros of the function are 5 and 6. Write an equation of the graph in general form.
This question makes no sense. If the x-intercepts are 5 and 6 how can there be a point (4,6) and still be a quadratic function. HELP please.
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Generally you would have y=ax^2+bx+c, and you are given the two zeros of the parabola. Try to narrow some of the equation using them.

Point (5,0):

Point (6,0):

Also you were given point B(4,6):

NOW you have a system of three equations in three unknowns (yes, they should be constants but currently you do not know their values) of a, b, and c.
---------------------
SYSTEM:

---------------------

Can you take the rest of the solution process from there?

Omitting the steps in solving that system, I found:

EQUATION:
{solution checks as correct}.
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