# SOLUTION: Match each graph with the correct equation on the right. This graph is a curve graph that goes from points(-2, 20) down to (0,0) and back up to (2,20) on the graph. The equations

Algebra ->  Algebra  -> Graphs -> SOLUTION: Match each graph with the correct equation on the right. This graph is a curve graph that goes from points(-2, 20) down to (0,0) and back up to (2,20) on the graph. The equations       Log On

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 Algebra: Graphs, graphing equations and inequalities Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Graphs Question 75695This question is from textbook Beginning Algebra : Match each graph with the correct equation on the right. This graph is a curve graph that goes from points(-2, 20) down to (0,0) and back up to (2,20) on the graph. The equations are: a)y=-x^2+1 b)y=2x c)y=x^2-4x d)y=-x=1 e)y=-x^2+3x f)y=x^2+1 g)y=x+1 h)y=2x^2 Thanks for your help. This question is from textbook Beginning Algebra Answer by ankor@dixie-net.com(15639)   (Show Source): You can put this solution on YOUR website!Match each graph with the correct equation on the right. This graph is a curve graph that goes from points(-2, 20) down to (0,0) and back up to (2,20) on the graph. : The equations are: a)y=-x^2+1 b)y=2x c)y=x^2-4x d)y=-x=1 e)y=-x^2+3x f)y=x^2+1 g)y=x+1 h)y=2x^2 : The problem here is, that none of the these equations would produce the given points, however the procedure is: : You can eliminate all the equations that have a numerical value because of the given point: 0,0 Cross out a, d, f, and g as possible answers : You can tell it is not a linear equation from the given points, Eliminate (b, : Also because the vertex is at 0, the 2nd term of the equation is 0 also Eliminate (c, (e : That leaves h) y = 2x^2 y = 2(-2^2) = 8 : Actually the equation that will produce the given points is y = 5x^2 y = 5(-2^2) = 20 or y = 5(+2^2) = 20 : Looks like this: