SOLUTION: Match each graph with the correct equation on the right.
This graph is a curve graph that goes from points(-2, 20) down to (0,0) and back up to (2,20) on the graph. The equations
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Question 75695This question is from textbook Beginning Algebra
: Match each graph with the correct equation on the right.
This graph is a curve graph that goes from points(-2, 20) down to (0,0) and back up to (2,20) on the graph. The equations are:
a)y=-x^2+1
b)y=2x
c)y=x^2-4x
d)y=-x=1
e)y=-x^2+3x
f)y=x^2+1
g)y=x+1
h)y=2x^2
Thanks for your help.
This question is from textbook Beginning Algebra
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Match each graph with the correct equation on the right.
This graph is a curve graph that goes from points(-2, 20) down to (0,0) and back up to (2,20) on the graph.
:
The equations are:
a)y=-x^2+1
b)y=2x
c)y=x^2-4x
d)y=-x=1
e)y=-x^2+3x
f)y=x^2+1
g)y=x+1
h)y=2x^2
:
The problem here is, that none of the these equations would produce the given
points, however the procedure is:
:
You can eliminate all the equations that have a numerical value because of the
given point: 0,0
Cross out a, d, f, and g as possible answers
:
You can tell it is not a linear equation from the given points, Eliminate (b,
:
Also because the vertex is at 0, the 2nd term of the equation is 0 also
Eliminate (c, (e
:
That leaves h) y = 2x^2
y = 2(-2^2) = 8
:
Actually the equation that will produce the given points is y = 5x^2
y = 5(-2^2) = 20
or
y = 5(+2^2) = 20
:
Looks like this:
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