SOLUTION: solve by graphing linear inequalities
3x-y<2
x+y>2
Algebra.Com
Question 75653: solve by graphing linear inequalities
3x-y<2
x+y>2
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
solve for y
Subtract 3x from both sides
Divide both sides by -1. When dividing by a negative, flip the inequality
Solve the 2nd equation for y:
Subtract x from both sides
So we can now graph and . We just graph the equations as we normally would if they were and . Here's the graph:
Now lets pick the test point (0,0) to see which region we should shade:
false. so we don't shade the region containing (0,0) for that inequality. This means we shade above the line (green line). Now lets test it on the 2nd inequality:
true. So we shade the region containing (0,0) for the inequality (the upper side of the red line). These regions intersect in the top most region above both of the lines. This is where the solution set lies.
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