SOLUTION: Find the equation of the line that passes through (5,0) and has a slope of -2/3

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Question 748581: Find the equation of the line that passes through (5,0) and has a slope of -2/3
Found 2 solutions by MathLover1, Cromlix:
Answer by MathLover1(20849)   (Show Source): You can put this solution on YOUR website!

the line that passes through (,) and has a slope of
Solved by pluggable solver: FIND a line by slope and one point

What we know about the line whose equation we are trying to find out:

  • it goes through point (5, 0)

  • it has a slope of -0.67



First, let's draw a diagram of the coordinate system with point (5, 0) plotted with a little blue dot:



Write this down: the formula for the equation, given point and intercept a, is

(see a paragraph below explaining why this formula is correct)

Given that a=-0.67, and , we have the equation of the line:



Explanation: Why did we use formula ? Explanation goes here. We are trying to find equation y=ax+b. The value of slope (a) is already given to us. We need to find b. If a point (, ) lies on the line, it means that it satisfies the equation of the line. So, our equation holds for (, ): Here, we know a, , and , and do not know b. It is easy to find out: . So, then, the equation of the line is: .

Here's the graph:



Answer by Cromlix(4381)   (Show Source): You can put this solution on YOUR website!
Using y- b = m(x - a)
with m = -2/3
and (5, 0)
y - 0 = -2/3(x - 5)
y = -2/3x + 10/3
or
3y = -2x + 10

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