SOLUTION: Without drawing a graph how can I determine (a) how many x-intercepts the parabola has (b) whether its vertex is above, below or on the x- axis? y = -x^2 + 2x-1

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Question 7460: Without drawing a graph how can I determine (a) how many x-intercepts the parabola has (b) whether its vertex is above, below or on the x- axis?

y = -x^2 + 2x-1

Answer by ichudov(507)   (Show Source): You can put this solution on YOUR website!
x intercepts is just another way of saying "roots". Find roots of this quadratic expression with y set to 0.
since coefficient in front of x is negative, the parabola is pointing downwards.
where its vertex is, depends on the roots.
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=0 is zero! That means that there is only one solution: .
Expression can be factored:

Again, the answer is: 1, 1. Here's your graph:


since both roots are same, its vertex is right on the x axis.

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