SOLUTION: I am not sure how to start the equation for this word problem, can you please help? Question: A consultant traveled 6 hours to attend a meeting. The return trip took only 5 hou

Question 73173: I am not sure how to start the equation for this word problem, can you please help?
Question: A consultant traveled 6 hours to attend a meeting. The return trip took only 5 hours because the speed was 10 miles per hour faster. What was the consultant's speed each way?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A consultant traveled 6 hours to attend a meeting. The return trip took only 5 hours because the speed was 10 miles per hour faster. What was the consultant's speed each way?
----------------
"Going" DATA:
Time = 6 hrs ; Rate = x mph ; Distance = rt=6x miles
---------
"Return" DATA:
Time = 5 hrs ; Rate = (x+10) mph : Distance = rt = 5(x+10) miles
------------
EQUATION:
Going distance = Return distance
6x = 5(x+10)
x=50 mph (Going speed)
x+10 = 60 mph (Return speed)
=====================
Cheers,
Stan H.
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