SOLUTION: FIND THE EQUATION OF THE HORIZONTAL LINE AND THE EQUATION OF THE VERTICAL LINE THAT PASS THROUGH THE POINT (0,8). EQ. OF HORIZONTAL LINE= EQ. OF VERTICAL LINE=

Question 72975: FIND THE EQUATION OF THE HORIZONTAL LINE AND THE EQUATION OF THE VERTICAL LINE THAT PASS THROUGH THE POINT (0,8).
EQ. OF HORIZONTAL LINE=
EQ. OF VERTICAL LINE=
Answer by bucky(2189) (Show Source): You can put this solution on YOUR website!
The point you are given is (0,8).
.
The equation for the horizontal line through this point is y = 8. Why? because for a horizontal
line, x can be any value on the x-axis and the corresponding value of y is always unchanged. In
this case y is always 8, regardless of the value of x.
.
If you had a horizontal line through the point (5, -2) the corresponding equation for this
horizontal line would be y = -2 because regardless of the value of x the value of y will
not change. It will always be -2 whether x is 5, -5, 0, 27, 5/4, square root of 2 , or whatever.
.
Now as to the vertical line through the point (0,8). This is sort of a similar situation, but
this time because the line is vertical, the value of x never changes. You can have any
value for y, but x remains as 0. So the equation for this line is x = 0. y can be 14,
27, - 4, -cube root of 19, 0, or whatever, and x never changes. It is always zero.
.
Notice something unusual about the line x = 0??? It is the equation for the y-axis ...
x is always zero, and y can have any value along the y-axis.
.
As another example, think about the graph of x = -10. What would it be. The answer is
that it would be a vertical line that crosses the x-axis at a value of -10.
.
Hope that this discussion gives you some insight into vertical and horizontal lines.

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