SOLUTION: How do you graph 6y+x Greater than or equal to a number...I just use that problem if you have to use another peoblem.. PLEASE HELP ME. in any way you can.
Algebra ->
Graphs
-> SOLUTION: How do you graph 6y+x Greater than or equal to a number...I just use that problem if you have to use another peoblem.. PLEASE HELP ME. in any way you can.
Log On
Question 72789: How do you graph 6y+x Greater than or equal to a number...I just use that problem if you have to use another peoblem.. PLEASE HELP ME. in any way you can. Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! How do you graph 6y+x Greater than or equal to a number...I just use that problem if you have to use another problem..
:
Let's use this equation"
3y + 6x >= 12
:
We want it in the general form (y=) in order to plot the coordinates in the
graph.
Subtract 6x from both sides and you have:
3y >= -6x + 12
:
We want y to have a coefficient of 1, divide equation by 3 and you have:
y >= -2x + 4
:
Ignore the inequality signs for a minute and chose some values for x and find y
:
Lets plot from -3 to + 3. Since this is a straight line you really only need
two but will make a table from -3 to 3 give you an idea of what's going on:
:
Start with x = -3, find y
Substitute -3 for x in the equation y = -2x + 4
y = -2(-3) + 4
y = +6 + 4
y = 10 when x = -3
:
Do the same for each value for x, the table should look like this:
x | y
-------
-3 | 10
-2 | 8
-1 | 6
0 | 4
+1 | 2
+3 | -2
plot each of these values on standard x/y graph paper,
your graph should look like this:
:
Remember its y >= -2x + 4 so there is not a unique solution, but an
"area of feasibility". As you look at the graph, this area would be
at the line (=) and above the line ">". On this graph it would be
the area above and to the right of the line'
:
:
Did this make sense to you, any questions.
