SOLUTION: ƒ(x)=x³-2x²-3x
Algebra.Com
Question 718318: ƒ(x)=x³-2x²-3x
Answer by josgarithmetic(39618) (Show Source): You can put this solution on YOUR website!
At what level of Algebra do you want to graph this? You should factor the polynomial and you have something easier to analyze.
f(x)=x(x^2-2x-3)
Roots at -1, 0, and 3. At x<-1, f is increasing. At x>3, f is increasing. Between -1 and 0, f is positive. Between 0 and 3, f is negative.
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