SOLUTION: Find the equation of the line tangent to the given circle and passing through the given point
1. x^2+y^2= 26 (4,6)
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Question 718082: Find the equation of the line tangent to the given circle and passing through the given point
1. x^2+y^2= 26 (4,6)
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Find the equation of the line tangent to the given circle and passing through the given point
1. x^2+y^2= 26 (4,6)
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There are 2 tangent lines thru the point.
The point, the tangent points and the center make right triangles.
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Find the distance from the point to the center of the circle
d = sqrt(52) = the hypotenuse
The radius is one side of the triangle, length = sqrt(26)
Use Pythagoras to find the distance from the point to the
tangent points, = sqrt(26)
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The tangent points are the intersections of the given circle and a circle of radius sqrt(26) centered at (4,6)
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Find the 2 intersections.
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The 2 lines are the lines thru the tangent point and (4,6)
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