SOLUTION: given the equatoin y=x a. find the lsope of a line parallel b. find the slop of a line perpendicular c. graph a perpendicular line that goes through the point (-2,-3)

Algebra ->  Graphs -> SOLUTION: given the equatoin y=x a. find the lsope of a line parallel b. find the slop of a line perpendicular c. graph a perpendicular line that goes through the point (-2,-3)      Log On


   

Question 71209: given the equatoin y=x
a. find the lsope of a line parallel
b. find the slop of a line perpendicular
c. graph a perpendicular line that goes through the point (-2,-3)
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
y=x
When in the form y=mx+%2B+b, m is the slope
For y=x, b = 0, and m = 1
a) A parallel line would have the same slope
as the equation, m=1
b) The slope of a perrendicular line has slope= -%281%2Fm%29
-%281%2F1%29+=+-1
c) By the point-slope formula,
%28y+-+%28-3%29%29+%2F+%28x+-+%28-2%29%29+=+-1
%28y%2B3%29+%2F+%28x%2B2%29+=+-1
y+%2B+3+=+-x+-+2
y+=+-x+-5
check this
The slope is -1, as needed. does it go through (-2,-3)?
-3+=+-%28-2%29+-+5
-3+=+2+-+5
-3+=+-3
OK
Pick any value for x, then find y. Now
you have 2 points and can graph it by hand or computer