SOLUTION: Just a quick question, why is it true that when you find 2 point satisfying a linear equation that you will have same graph for the line represented by the equation??

Algebra.Com
Question 70593: Just a quick question, why is it true that when you find 2 point satisfying a linear equation that you will have same graph for the line represented by the equation??
Found 2 solutions by checkley75, stanbon:
Answer by checkley75(3666)   (Show Source): You can put this solution on YOUR website!
Y=mX+B IS THE STANDARD EQUATION FOR A LINE THROUGH TWO POINTS WITH A SLOPE(m) & A Y INTERCEPT (b). THIS LINE IS EXPRESED AS AN EQUATION & A GRAPH OF THE LINE THROUGH THE TWO DEFINED POINTS.
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
Every two pair of points has the same slope and
the equation only has one y-intercept. The slope
gives you "m"; the y-intercept gives you "b".
The equation of the line is y=mx+b and m and b
do not change no matter what two points on the
line are used.
Cheers,
Stan H.

RELATED QUESTIONS

Why is it true that any two points satisfying a linear equation will give you the same... (answered by MelanieBCC)
Why is it true that any two points satisfying a linear equation will give you the same... (answered by venugopalramana)
Why is it true that any two points satisfying a linear equation will give you the same... (answered by fractalier)
Why is it true that any two points satisfying a linear equation will give you the same... (answered by stanbon)
Why is it true that any two points satisfying a linear equation will give you the same... (answered by Alan3354)
1.) when solving a linear inequality, why do you always solve for y? 2.) when graphing (answered by longjonsilver)
Why is it true that any two points satisfying a linear equation give you the same graph... (answered by richard1234)
Hi. I have a question concerning how exponents 'work'. I understand how exponents 'work' (answered by richwmiller,smithsac,richard1234,MathTherapy)
Hi! I am going nuts with this problem. They gave me a graph with a "launch area" and... (answered by richwmiller)