SOLUTION: 20x+3y=20 and -20x+5y=60 using elimination
20x+3y=20 -20x+5(10)=60
-20x+5y=60 -20x+50= 60
----------- -50 -50
0+8y=80 --- ---
Algebra.Com
Question 700254: 20x+3y=20 and -20x+5y=60 using elimination
20x+3y=20 -20x+5(10)=60
-20x+5y=60 -20x+50= 60
----------- -50 -50
0+8y=80 --- ---
-- -- -20x-110
8 8 ---- ---
y=10 x=5.5
My question is, did I get the right answer, if not how did I mess up?
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
20x+3y=20 and -20x+5y=60 using elimination
20x+3y=20 -20x+5(10)=60
-20x+5y=60 -20x+50= 60
----------- -20x= -50 +60
0+8y=80 --- ---
-- -- -20x= 10
8 8 ---- ---
y=10 x=-0.5
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