SOLUTION: what line passes through 8,10 and is parallel to the graph of y=8/3x+7

Question 698971: what line passes through 8,10 and is parallel to the graph of y=8/3x+7

Found 2 solutions by mananth, stanbon:
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
y = 2 2/3 x + 7
Compare this equation with y=mx+b
slope m = 8/3
The slope of a line parallel to the above line will be the same
The slope of the required line will be 8/3
m= 8/3 ,point ( 8 , 10 )
Find b by plugging the values of m & the point in
y=mx+b
10 = 64/ 3 + b
b= -34/3
m= 8/3
Plug value of the slope and b in y = mx +b
The required equation is y = 8/3 x -34/ 3

m.ananth@hotmail.ca

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
what line passes through 8,10 and is parallel to the graph of y=8/3x+7
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slope of the line must be (8/3).
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Form: y = mx + b
You know y = 10 when x = 8, and m = 8/3 ; solve for "b":
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10 = (3/8)8 + b
b = 10-3
b = 7
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Equation:
y = (8/3)x+7
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Cheers,
Stan H.
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