# SOLUTION: Write the equation of the line passing through (3, –7) and (–6, –7).

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 Click here to see ALL problems on Graphs Question 69840: Write the equation of the line passing through (3, –7) and (–6, –7). Answer by Edwin McCravy(8909)   (Show Source): You can put this solution on YOUR website!``` Write the equation of the line passing through (3, –7) and (–6, –7). Use the slope formula: y2 - y1 m = ————————— x2 - x1 where (x1, y1) = (3, -7) and (x2, y2) = (-6, -7) (-7) - (-7) -7 + 7 0 m = ————————————— = ———————— = ———— = 0 (-6) - (3) -6 - 3 -9 Now substitute in the point slope formula: y - y1 = m(x - x1) y - (-7) = (0)( x - (-6) ) y + 7 = 0 y = -7 which is a horizontal line 7 units below and parallel to the x-axis. You could have just plotted the points and drawn a line through them, and observed that every point on the line has the y-value -7, and just immediately written that y always = -7, or y = -7. Edwin```