SOLUTION: Graph the system of equations. Then determine whether the system has "no solution" , "one solution", or "infinite solutions". If the system ha one solution name it. Y= -1/2x + 3

Question 692098: Graph the system of equations. Then determine whether the system has "no solution" , "one solution", or "infinite solutions". If the system ha one solution name it.
Y= -1/2x + 3
Y= 2x - 2
(it shows just a plain graph)
I know it's "y= m(x) + b" but idk if I should use m = y2 - y1 over x2 - x1 I'm really confused.
Answer by ReadingBoosters(3246) (Show Source): You can put this solution on YOUR website!
You are given the equation for both lines in the slope-intercept form(y=mx+b).
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You can determine the solution to the system of equations algebraically and graphically.
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To solve it graphically, you will graph each line and the solution is where the lines intersect.
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Just by looking at the equations, you can tell that not only will they intersect, but the lines are perpendicular.
Perpendicular lines have negative inverse/reciprocal slope.
In the first line y=-1/2x + 3, the slope is .
In the second line y= 2x - 2, the slope is 2.
is the negative reciprocal of 2
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To graph a line, find the x and y intercept and draw a line through them.
the y intercept is b in the y=mx+b format
the x intercept is x when y is 0
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For y = x+3
y intercept is 3, so plot (0, 3)
x intercept is found by:
0 = x + 3
-3 = x
-3(-2) =
6 = x, so plot (6, 0)
Then draw a line through the intercepts, so that it looks like:

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For y = 2x - 2
y intercept is -2, so plot (0, -2)
x intercept is found by
01 = 2x - 2
2 = 2x
1 = x, so plot (1, 0)
Then draw a line through the intercepts and your graph should look like:

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The "one solution" to the system is the point where they intercept,
(,)
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Algebraically, set the two equations equal to each other and solve for x
==> multiply both sides by 2
-1x + 6 = 4x - 4
6 + 4 = 4x + x
10 = 5x
x=2
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Plug in x into either equation and solve for y
y = 2(2) - 2 = 4-2
y = 2
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Confirmed, the solution/point of intersection is (2,2)
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