SOLUTION: Find an equation of the line tangent to the graph of y=x^2-x+1-ln(x+4) at (-3,13).
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Question 682699: Find an equation of the line tangent to the graph of y=x^2-x+1-ln(x+4) at (-3,13).
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
)
\ =\ -6\ -\ 1\ -\ 1\ =\ -8)
Use the point-slope form
)
Simplify as required.
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
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