SOLUTION: How would I test for intercepts. I have to show the steps to test the intercepts. If anyone could help me, that would be fantastic!!!!
X^2+y^2+12x+10y+61=16
X^2+12x+36+y^2+
Algebra.Com
Question 672608: How would I test for intercepts. I have to show the steps to test the intercepts. If anyone could help me, that would be fantastic!!!!
X^2+y^2+12x+10y+61=16
X^2+12x+36+y^2+10y+25=-45+36+25
(x+6)^2+(y+5)^2=16
C (-6, -5) and r=4
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
How would I test for intercepts. I have to show the steps to test the intercepts. If anyone could help me, that would be fantastic!!!!
X^2+y^2+12x+10y+61=16
X^2+12x+36+y^2+10y+25=-45+36+25
(x+6)^2+(y+5)^2=16
C (-6, -5) and r=4
**
x-intercepts, set y=0
(x+6)^2+(y+5)^2=16
(x+6)^2+(0+5)^2=16
(x+6)^2+25=16
(x+6)^2=-9
(x+6)=±√-9=±3i
no real roots
x-intercepts: none
..
y-intercepts, set x=0
(0+6)^2+(y+5)^2=16
36+(y+5)^2=16
(y+5)^2=-20
(y+5)^2=-20
(y+5)=±√-20=±√20 i
no real roots
y-intercepts: none
RELATED QUESTIONS
Hi eberyone, I was wondering if anyone could show me how to solve the following problem;
(answered by Earlsdon)
hey there,
I really don´t know in which category this goes, but my teacher gave me this... (answered by josgarithmetic)
I have a test tomorrow and am having a lot of trouble with quadratic equations. i... (answered by jim_thompson5910)
Write a quadratic function whose graph has the given characteristics: x-intercepts... (answered by scott8148)
Hi I would like some help in solving to find the x and y intercepts of the equation:... (answered by solver91311)
I am trying to find the y-intercepts of {{{ x+2=(y+1)^2 }}} all I have been able to... (answered by stanbon,ewatrrr)
Okay so I have this equation:
h(x) = x^2 - 1
.........---------------... (answered by josgarithmetic)
Could someone help me with a few system of equations problems please? These ones are to... (answered by jim_thompson5910)
I need some help on an algebra test. Here is the question:
Simplify. Make sure to... (answered by stanbon)