Hi,

y = x^2 + 2x + 2   Pt(0,2) on the curve

y =  x^2 + 2x +1 -1 + 2  

y = (x + 1)^2 + 1  parabola, V(-1,1) line of symmetry x = -1

Graph, NO real solutions



 

Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
 Use a graphing calculator to get











The green graph NEVER crosses the x axis. So there are NO real solutions. 

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