SOLUTION: 2k+4+1+12k=11(k-10)-10(k-5)

Question 663378: 2k+4+1+12k=11(k-10)-10(k-5)
Answer by ReadingBoosters(3246) (Show Source): You can put this solution on YOUR website!
Starting with
2k + 4 + 1 + 12k = 11(k-10)-10(k-5)
Combine like terms on the left and distribute on the right
14k + 5 = 11k - 110 - 10k + 50
Combine like terms on the right
14k + 5 = k - 60
Group like terms
14k - k = -60 - 5
13k = 55
k = 55/13 = 4 3/13
RELATED QUESTIONS
4(2k-1)=-10(k-5) (answered by checkley77)

2k-10/7=8?... (answered by stanbon)

Find the Value of K K.......3+K.........-10 1-K......2-K......... 5 = 48 2... (answered by Edwin McCravy)

Evaluate 37 ∑ (2K-10)... (answered by tommyt3rd)

3/4 k+1= 3/8 -... (answered by terbear1963)

-8(k-4)=8(1-2k) (answered by jim_thompson5910)

9(K-4)+2K=2(K-1)=7K (answered by rapaljer)

9(k-4)+2k=2(k-1)+7k (answered by jim_thompson5910)

9(k-4)+2k=2(k-1)+7k (answered by s0197469)