SOLUTION: Find the center and radius of the circle given by the equation
x^2+y^2+4x+4y−28=0
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Question 662039: Find the center and radius of the circle given by the equation
x^2+y^2+4x+4y−28=0
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find the center and radius of the circle given by the equation
x^2+y^2+4x+4y−28=0
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Complete the square on the x-terms and on the y-terms:
x^2 + 4x + 4 + y^2 + 4y + 4 = 28 + 4 + 4
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(x+2)^2 + (y+2)^2 = 34
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center: (-2,-2)
radius: sqrt(34)
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Cheers,
stan H.
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