SOLUTION: Find two consecutive integers such that the sum of 2 times the first integer and 4 times second integer is 46.

Algebra.Com
Question 66177: Find two consecutive integers such that the sum of 2 times the first integer and 4 times second integer is 46.
Answer by checkley71(8403)   (Show Source): You can put this solution on YOUR website!
2x+4(x+1)=46
2x+4x+4=46
6x=46-4
6x=42
x=7 solution then
7+1=8 solution
proof
2*7+4*8=14+32=46

RELATED QUESTIONS

find two consecutive integers such that the sum of 2 times the first integer and 4 times... (answered by stanbon)
Find two consecutive integers such that the sum of 2 times the first integer and 4 times... (answered by Paul)
Find two consecutive integers such that the sum of 2 times the first integer and 4 times... (answered by Nate)
Find two consecutive integers such that the sum of 2 times the first integer and 4 times... (answered by psbhowmick)
Find two consecutive integers such that the sum of 2 times the first integer and 4 times... (answered by Socom491)
Find two consecutive integers such that the sum of 2 times the first integer and 4 times... (answered by Nate)
Find two consecutive integers such that the sum of 2 times the first integer and 4 times... (answered by Earlsdon)
Find two consecutive integers such that the sum of 2 times the first integer and 4 times... (answered by checkley75)
I cannot understand how to do this problem: Find two consecutive integers such that... (answered by ichudov)