# SOLUTION: The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times the length of the base. If the perimeter is 29 cm, find the length of one of the equal legs.

Algebra ->  Algebra  -> Graphs -> SOLUTION: The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times the length of the base. If the perimeter is 29 cm, find the length of one of the equal legs.      Log On

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 Click here to see ALL problems on Graphs Question 66169: The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times the length of the base. If the perimeter is 29 cm, find the length of one of the equal legs.Answer by algebrapro18(206)   (Show Source): You can put this solution on YOUR website!if x is equal to the length of the base of the triangle then 4x-8 is equal to the length of the two remaining sides. Now just solve the equation for x. 2(4x-8) + x = 29 8x - 16 + x = 29 9x - 16 = 29 9x = 45 x = 5 so the length of one of the legs is: 4(5)-8 20-8 12